不是特别的清楚,大概是这样的dif:=ema(close,short)-ema(close,long);dea:=ema(dif,mid);ref(dif,3)>ref(dea,3) and ref(dif,4)<ref(dea,4) and ref(dif,2)>ref(dea,2) and ref(dif,1)>ref(dea,1) and dif<=dea*0...
new users sign up below 新的用户在下面注册please fill out the form for age verification only!请填好下面的表格,仅用于年龄证明!username:用户名password:密码first name:名字last name 姓氏email address 电子.