{20}aa:=ma(c,20);ref(aa,1)>ref(aa,2) and cross(c,aa);------------------------------------{20日均线下拐选股}aa:=ma(c,20);ref(aa,1)<ref(aa,2) and cross(aa,c); 20210311
ma1:=ma(c,10);ma2:=ma(c,20);aa:=ma1-ma2;cc:=between(aa-ref(aa,1),-0.01,0.01) and ma1>ma2 and ma1>ref(ma1,1) and ma2>ref(ma2,1);xg:every(cc,3); (看你问了很多啊。试试看符合要求不?)