噢噢,好的!t1:=ma(c,5)>ma(c,10) and ma(c,10)>ma(c,20) and ma(c,20)>ma(c,60);t2:=count(v<ref(v,1) and c>ma(c,5),4)>=3;t3:=hhv(h,3)/llv(l,3)<0.05;xg:t1 and t2 and t3;希望能帮到你! 20210311
ma5:=ma(c,5);ma10:=ma(c,10);bias1:=(ma5-ma(ma5,6))/ma(ma5,6)*100;bias2:=(ma10-ma(ma10,6))/ma(ma10,6)*100;ma30:=ma(c,30);xg:ma30>ref(ma30,1) and bias1<3 and bias2<3 and count(c/ref(c,1)>1.0...