角度d:=atan((kdj.d/ref(kdj.d,1)-1)*100)*180/3.1416;xg:ref(kdj.j,1)<ref(kdj.j,2) and between(ref(kdj.j,1)-ref(kdj.d,1),0,5) and 角度d>30 and kdj.j>ref(kdj.j,1);(已测试) 20210311
角度d:=atan((kdj.d/ref(kdj.d,1)-1)*100)*180/3.1416;涨停:=o>ref(h,1) and c/ref(c,1)>1.099;xg:ref(涨停,5) and ref(kdj.j,1)<ref(kdj.j,2) and between(ref(kdj.j,1)-ref(kdj.d,1),0,5) and 角度d>30 and kd...
加我1924270772 | 五 "kdj.j"<0 and ("cci.cci"-200)-200)/200<0.05 and c>ma(c,5)*1.1; 追问 公式不能通过烦再改一============================================ "kdj.j"<0 and ((...