{xggs-}m5:=ma(c,5);m10:=ma(c,10);m20:=ma(c,20);m40:=ma(c,40);m50:=ma(c,50);xg:cross(c,m50)&m50>m5 and m50>m10 and m50>m20 and m50>m40;通过tdx测试。{个人看法,仅供参考。} 20210311
公式如下,在通达信中测试通过,你试试。mv5:=ma(v,5);mv10:=ma(v,10);mv20:=ma(v,20);mv30:=ma(v,30);tj1:=mv5>mv10 and mv10>mv20 and mv20>mv30;tj2:=mv5>ref(mv5,1) and mv10>ref(mv10,1) and mv20>ref(mv20,1) a...