{公式1}every(vol>=ref(vol,1),3) and (vol/capital*100)>=3 and c>ma(c,5);{公式2}a1:=ma(c,5); a2:=ma(c,10); a3:=ma(c,20); every(vol>=ref(vol,1),3) and (vol/capital*100)>=3 and c>ma(c,5) and...
一:aa:=ma(c,5)>ma(c,20) and ma(c,20)>ma(c,60);bb:=c>ma(c,5);cc:=vol/capital*100>3;aa and bb;二:aa:=ma(c,5)>ma(c,20) and ma(c,20)>ma(c,60);bb:=c>ma(c,5);cc:=vol/capital*100>3;aa and bb and cc;
好像写过了。下载最新的5分钟数据,选股周期设为5分钟进行选股。ma(c,5)>ref(ma(c,5),1) and ma(c,10)>ref(ma(c,10),1) and ma(c,20)>ref(ma(c,20),1) and ma(c,30)>ref(ma(c,30),1) and ma(c,40)>ref(ma(c,40),1) and ma(c,50)>...
b:ref(h,1)>ref(c,1)and(ref(h,1)-ref(c,2))/ref(c,2)>5/100 and c>=ref(h,1);你的上影线超过5%这话我没理解清楚.我对你问题的是:只要昨天有上影线(不论长短)并且昨天最高点超过前天收盘价的5%,今天的收盘价高于等于昨天的最高价.如理解错了可再联系.
ema13:=ema(c,13),colorwhite;ema21:=ema(c,21),coloryellow;ema34:=ema(c,34),colorff00ff;ema60:=ma(c,60),colorffcc66;var2:=(2*close+high+low)/4;var3:=if(year>=2099 and month>2,0,1);var4:=llv(low,5)...
ma1:=ma(close,5);ma2:=ma(close,10);ma3:=ma(close,20);ma4:=ma(close,60);xg:count(cross(ma1,ma2),3)=1 and count(cross(ma1,ma3),3)=1 and count(cross(ma1,ma4),3)=1;