var1:=(2*close+high+low)/4;var2:=llv(low,34);var3:=hhv(high,34);xx:=ema((var1-var2)/(var3-var2)*100,13);yy:=ema(0.667*ref(xx,1)+0.333*xx,2);cross(xx,yy) and xx<20 ;
{ok。测试通过}ref(c,1)<ref(o,1) and c>o and c>ref(o,1) and o<=ref(c,1) and ma(c,5) > ref(ma(c,5),1) and ma(c,13) > ref(ma(c,13),1) and ma(c,21) > ref(ma(c,21),1);