ma65:=ma(c,65);ma250:=ma(c,250);bb:count(cross(ma(c,65),ma(c,250)),250);xg:=ma250>ref(ma65,1);cross(ma250,ma65) and xg and bb;cross(ma250,ma65) and xg and bb;这句错误,不知道你想表达的意思。bb大于0的情况下,那么cross(ma250,ma65),上穿就是250大于65,何必在要求xg 的条件? 去掉xg就可以了。 20210311
{通达信测试通过买点出现,卖点出现选股}买:(zig(3,5)>ref(zig(3,5),1)) and (ref(zig(3,5),1)<=ref(zig(3,5),2)) and (ref(zig(3,5),2)<=ref(zig(3,5),3));----------------------------------------------卖:(zig(3,5)<ref...