n:=30;m5:ma(c,5);m10:ma(c,10);上升通道:=m5>m10 or m10>ref(m10,1);m10支撑:=abs(ref(c,1)/m10-1)<0.01 and c/ref(c,10)>=1;mm:=count(cross(m5,m10),n);v1:=上升通道 and mm=1 and m10支撑 ;v2:=上升通道 and mm=2 ...
a1:=3*sma((c-llv(l,55))/(hhv(h,55)-llv(l,55))*100,5,1)-2*sma((c-llv(l,55))/(hhv(h,55)-llv(l,55))*100,5,1);:=ema(a1,5);a2:=(黑马线-ref(黑马线,1))/ref(黑马线,1)*100;xg:a2<-10 and a2>ref(a2,1);这样似乎效果更佳。红柱倒见...