{试试看}down:=o>c;x1:=count(down,5)=4;x2:=(hhv(c,20)-llv(c,1))/ llv(c,1)/50*100;x3:=(min(c,o)-l)/(h-l)>0.667 and (h-max(c,o))/(h-l)<0.333 and (c-o)<0.1; x1 and x2 and x3 ;
做个记号,等下来解决 ------------------------------------tj:=filter(c,239)>0;tjj:=sum(tj,0);tja:=const(tjj);a7:=c-ref(c,1);a8:=if(((tja<2 or period!= 0) or period!= 0),5000*ema(ema(a7,11),11)/ema(ema(abs(...
公式1: ma1:=ma(c,5);ma2:=ma(c,10);ma3:=ma(c,20);xg:cross(ma1,ma3) and cross(ma2,ma3);公式2: ma1:=ma(c,10);ma2:=ma(c,20);xg:count(cross(ma1,ma2),10)=1 and l<ma2 and c>ma2;