要的公下,通过的a5:=ma(c,5);a10:=ma(c,10);a20:=ma(c,20);aa:=max(max(a5,a10),a20);aaa:=min(min(a5,a10),a20);aaaa:=aa/aaa<1.1;bb:=count(aaaa,12)=12;zm:capital <5000000 and bb;
a1:=c<o and c<ref(c,1);阳线贯穿:ref(a1,1)>0 and o<ref(c,1) and c>(ref(c,1)+(ref(o,1)-ref(c,1))/2);a1:=c<o and c<ref(c,1);孕育:ref(a1,1)>0 and c>ref(c,1) and c<ref(o,1) and o>...