xg:ref(c<o and h/l>1.03,1)and c>o and c/ref(c,1)-1>ref(h/l-1,1)*0.5 and macd.macd(count(ma(c,10)(c,20)and ma(c,20)(c,60),30)=30)and hhv(h,10)/llv(l,10)>1.05;
{1:a柱为涨幅超过4%的阳线且换手率大于3%, 2:b c d至少 柱有两根换手率小于a柱(是任意两柱) 3:d 柱收盘价大于a柱收盘价} ref(c,3)>ref(c,4)*1.04 and hsl>0.03 and count(v=2 and c>ref(c,3);a:=ref(c,3)>ref(c,4)*1.04 and hsl>0.03;{a柱为涨幅超过4%...
bb:=ma(c,5)>ma(c,20) and ma(c,20)>ma(c,60) and ma(c,60)>ma(ref(c,60),1);aa:=barssincen(v>ref(v,1)*2,50);ll:=ref(l,aa);sc:l<ll and bb;您好公式已经测试通过,是符合您要求的,但是我不知道您想达成什么样的效果,也欢迎您进一步追问,祝愿您投资顺...