diff:=ema(c,12)-ema(c,26);dea:=ema(diff,9);t:=barslast(dea);dd1:=count(cross(diff,dea),t)>=1 and cross(diff,dea);dd2:=v>ref(ma(v,5),1)*1.5;dd3:=(c/ref(c,1)-1)*100;轴上第一金叉:=cross(diff,dea)and dea&...
你的选股思路还是具有可操作性的,是属于会独立思考的股民,公式已经做好,在通达信中测试通过,你试试。ma3:=ma(c,3);ma5:=ma(c,5);ma10:=ma(c,10);ma30:=ma(c,20);jx:=ma5>ma10 and ma10>ma30 and ma5>ref(ma5,1).