ok了(ref(c>o,5) and ref(c<o,4) and ref(c>o,3) and ref(c<o,2) and ref(c<o,1) and c>o) or(ref(c>o,5) and ref(c<o,4) and ref(c<o,3) and ref(c>o,2) and ref(c<o,1) and c>...
wy1001:=(2*close+high+low)/4;wy1002:=ema(wy1001,2);wy1003:=ema(wy1002,2);wy1004:=ema(wy1003,2);xys0:=(wy1004-ref(wy1004,1))/ref(wy1004,1)*100;xys0>0 and count(xys0>0,2)=1;原来的航海家,现在的破经传,靠不住啊!