{以下填入缺省值}n1:=5;n2:=10;n3:=30;m1:=ma(c,n1), m2:=ma(c,n2);m3:=ma(c,n3);xg:m1>m2 and m1>m3 and m2>m3 and m1>ref(m1,1) and m2>ref(m2,1) and m3>ref(m3,1);{个人看法,仅供参考。} 20210311
ma1:=ma(c,5);ma2:=ma(c,10);ma3:=ma(c,20);ma4:=ma(c,30);天数1:=barslast(cross(ma1,ma2));天数2:=barslast(cross(ma1,ma3));xg:天数1>天数2 and 天数2>0 and cross(ma1,ma4);(5日均线上穿十日均线再上穿20均线再上穿30日均线,这样信号就比较少了。再加...
公式如下:ma5:=ma(c,5);ma10:=ma(c,10);ma20:=ma(c,20);ma40:=ma(c,40);condtion_a:=ma5>ma10 and ma10>ma20 and ma20>ma40;{判断是否多头排列}condtion_b:=(o-ma5)/ma5*100>=-1;{判断是否跌穿五天的成本均线}xg:condtion_a and c...
ma5:=ma(close,5);ma10:=ma(close,10);ma20:=ma(close,20);lb:=v/fromopen/(sum(ref(v,1),5)/1200);dt:=barslastcount(ma5>ref(ma5,1) and ma10>ref(ma10,1) and ma20>ref(ma20,1));xg:lb>2 and dt>0...