这样形态是少见,你或举例。下面是公式: t1:=ref(v,1)>=ref(v,2)*3;t2:=((ref(c,1)-ref(c,2))/ref(c,2)*100)>8;t3:=v(v,1)and between((c-ref(c,1))/ref(c,1)*100,-1,1);xg:(t1 and t2 and t3);
公式1: ma1:=ma(c,5);ma2:=ma(c,10);ma3:=ma(c,20);xg:cross(ma1,ma3) and cross(ma2,ma3);公式2: ma1:=ma(c,10);ma2:=ma(c,20);xg:count(cross(ma1,ma2),10)=1 and l<ma2 and c>ma2;