ma5:=ma(c,5);ma10:=ma(c,10);bias1:=(ma5-ma(ma5,6))/ma(ma5,6)*100;bias2:=(ma10-ma(ma10,6))/ma(ma10,6)*100;ma30:=ma(c,30);xg:ma30>ref(ma30,1) and bias1<3 and bias2<3 and count(c/ref(c,1)>1.0...
您的描述可理解为:最20日振幅大10%,目前股价中,正向20靠拢。把这样的股票选出来。公式如下(我又细化了一下):ar1:=(hhv(h,20)-llv(l,20))*100/llv(l,20)>10;ar02:=(c,5)<((c,5),1);ar2:=count(ar02,5)=5;ar3:=count(l/(c,20)<1.002 and h>ma(c,20),3)&...