boll:=ma(close,n);upper:=boll+2*std(close,n);lower:=boll-2*std(close,n);cross(ma(c,5),ma(c,10)) and upper<ref(upper,1) and lower>ref(lower,1) and ref(upper,1)<ref(upper,2) and ref(lower,1)>...
condtion_a:=cross(ma(c,5),ma(c,10));condtion_b:=barslast(condtion_a)>0;condtion_c:=count(ccondtion:condtion_b and condtion_c and not(cross(ma(c,10),ma(c,5)));
因为这几个条件一般不会同时满足,你的原意应该 是在一指定的天数n内达到这些条件。因此我在公式中给你加了一个参数n,你试试。 ma5:=ma(c,5);ma10:=ma(c,10);ma30:=ma(c,30);ma130:=ma(c,130);xg:count(cross(ma5,ma10),n)>0 and count(cross(ma5,ma30),n)>0 and count(c...
缘分。不要使用别人的均线交叉,不准a1:=(close-ma(c,18))>0;a2:=count(a1,m)<3;a3:=count(a1,m)>1;a4:=abs(c-ma(c,x))/ma(c,18)<0.004;a5:=c-ref(c,1)<0;a6:=c>=ma(c,18);a2 and a3 and a4 and a5 and a6;不懂加入我的百度...