amo:=amount;maamo1:=ma(amo,10);maamo2:=ma(amo,20);maamo3:=ma(amo,30); aa:=ma(c,5)>ma(c,10) and ma(c,10)>ma(c,30) and ma(c,30)>ma(c,60) and ma(c,60)>ma(c,120);cross(maamo1,maamo2) and aa a...
n:=20;n1:=15;t1:=ref(hhv(h,n)/llv(l,n),1)(1+n1/100)and barscount(c)>n;t2:=t1=1 and c>=ref(hhv(h,n),1)and v>ref(v,1)and c<o and c>ref(c,1);xg:ref(t2,1)=1 and v(v,1)and c>ref(h,1);n是盘整...
公式如下,在通达信中测试通过,你试试。mv5:=ma(v,5);mv10:=ma(v,10);mv20:=ma(v,20);mv30:=ma(v,30);tj1:=mv5>mv10 and mv10>mv20 and mv20>mv30;tj2:=mv5>ref(mv5,1) and mv10>ref(mv10,1) and mv20>ref(mv20,1) a...