l1:= ref(c,2)>ref(o,2) and ref(c,1)<ref(o,1) and c<o and (ref(o,1)-ref(c,1))/ref(o,1)>0.03 and ref(o,1)/ref(c,1)>o/c;l2:= ref(v,2)>ref(v,1) and ref(v,2)>v;l3:= ref(c,2)>ref...
m5:=ma(c,5);m10:=ma(c,10);m24:=ma(c,24);m72:=ma(c,72);b1:=abs(m5-m72)/m72<0.01;b2:=abs(m10-m72)/m72<0.03;b3:=abs(m24-m72)/m72<0.03;x:=b1 and b2 and b3 and c>m72; ex**t(x,3);
tt:=v*100/capital;dif:=ema(dclose,12)-ema(dclose,26);dea:=ema(dif,9);aaa:=(dif-dea)*2*60;起爆:cross(aaa-ref(aaa,1),15) and finance(7)<350000000 and c>3 and vol>0;
前期至今:=90;{自己可调整}涨幅下限:=2;涨幅上限:=3;{建议调整为4}cci下限:=-200;{建议调整为-180}cci上限:=-150;{建议调整为-160}光头:=c=h; {光头光脚:c=h and o=l;}{建议:只光头不光脚,否则信号太少}小阳涨幅:=open<=ref(c,1) and range(c/ref(c,1),1+涨幅下限/100,1+涨幅上限/100);...
说实话,当我按着你的要求编完后,经测试,吓我一跳,你这土办法效果还真挺灵的,成功率比较高,****干过飞机大炮。xg1:(ref(c,3)-ref(c,2))/ref(c,2)>=0.03 and ref(c,1)(c,2)and(((o-l)>(c-o)*2 and c>o)or((c-l)>(o-c)*2 and o>c));我想追问一句,你是怎么想出来这土办法的...