count(h=hhv(h,60),5)=1 and (count(c<o,4)=4 or count(c<ref(c,1),4)=4);{统计5日中满足最高价=60日内最高价的最高值的天数=1 and (统计4日中满足收阴线的天数=4 or 统计4日中满足收盘价<昨收的天数=4)} 20210311
m1:=ma(close,5);m2:=ma(close,10);m3:=ma(close,20);m4:=ma(close,30);dif:=ema(close,12)-ema(close,26);dea:=ema(dif,9);xg:m1>m2>m3>m4 and high>m1 and dif>dea and ma(v,5)>ma(v,10);公式大概如...