求**编写通达信公式 光头光脚阳线贯穿5.10.20.30均线,在5天内。条件一:光头光脚阳线 条件二:贯穿5.10.20.30均线条件三:在5天内tj1:=c>o and c=h and l=o;tj2:=l<=min(ma(c,5),min(ma(c,10),min(ma(c,20),ma(c,30)))) and c>=max(ma(c,5),max(ma(c,10),max(ma(c,20),ma(c,30))));xg: count(tj1 and tj2 ,5)>=1; 20210311
通信达均量线多头排列: mv1:=ma(v,5);mv2:=ma(v,10);mv3:=ma(v,20);mv4:=ma(v,30);xg:mv1>mv2 and mv2>mv3 and mv3>mv4;通信达成交金额线多头排列: mam1:=ma(amount,5);mam2:=ma(amount,10);mam3:=ma(amount,20);mam4:=ma(amount,...
mv5:=ma(amount,5);mv10:=ma(amount,10);mv20:=ma(amount,20);mv30:=ma(amount,30);tj1:=mv5>mv10 and mv10>mv20 and mv20>mv30;tj2:=mv5>ref(mv5,1) and mv10>ref(mv10,1) and mv20>ref(mv20,1) ...
ma5:=ma(c,5);ma10:=ma(c,10);ma20:=ma(c,20);xg1:=cross(l,ma5) and cross(l,ma10) and cross(l,ma20);xg2:=cross(h,ma5) and cross(h,ma10) and cross(h,ma20);同穿:xg1 or xg2;若解决了问题请及时采纳,多谢!