{这是我编的五线开花,把 ma60:=ma(close,60);改成ma50:=ma(close,50);和去掉ma120:=ma(close,120);下面相应的ma120去掉;ma60改ma50;}ma5:=ma(close,5);ma10:=ma(close,10);ma20:=ma(close,20);ma30:=ma(close,30);ma60:=ma(close,60);ma120:=ma(close,120);ma120>=ref(ma120,1)and ma60>ref(ma60,1)and ma60< ma30 and ma30>ref(ma30,1) and ma30<ma20 and ma20>ref(ma20,1) and ma20 <= ma10 and ma10 >= ref(ma10,1)and ma5>ref(ma5,1) and ref(ma5,1)<=ref(ma5,2) and cross(ma5,ma10)and dyna**(7)>ma5; 20210311
a1:=ma(close,5);a2:=ma(close,10);a3:=ma(close,20);a4:=ma(close,60);a1>a2 and a2>a3 and a2>ref(a2,1)and a3>ref(a3,1)and a4>ref(a4,1)and a3>a4 and abs(c/a3);
ma(c,5)>ma(c,10) and ma(c,10)>ma(c,20) and ma(c,20)>ma(c,30) and ma(c,5)>ref(ma(c,5),1) and ma(c,10)>ref(ma(c,10),1) and ma(c,20)>ref(ma(c,20),1) and ma(c,30)>ref(ma(c,30),1) and ...
ma5:=ma(c,5);ma10:=ma(c,10);ma20:=ma(c,20);ma40:=ma(c,40);condtion_a:=ma5>ma10 and ma10>ma20 and ma20>ma40;{判断是否多头排列} condtion_b:=(o-ma5)/ma5*100>=-1;{判断是否跌穿五天的成本均线} xg:condtion_a and cond...