var1:=indexc; var2:=ma(var1,6); var3:=ma(var1,24); var4:=ma(var1,32); var5:=ma(var1,62); v**:=ma(var1,105); var7:=var5<ref(var5,1) and v**<ref(v**,1) and var5<v***0.98; var8:=var4>var2*1.11 and var3>var2*1.095; var9:=var2>var1*0.95;百发百中:=var7 and var8 and var9 and close/cost(8)<=0.8 and (close>open or close<open) and (ref(close,1)>ref(open,1) or ref(close,1)<ref(open,1)); var1n:=ma(close,5); var2n:=ma(close,10); var3n:=(var1n-close)/close>3/100; var4n:=(var2n-var1n)/var1n>0.03; var5n:=llv(close,30)=llv(close,120); 底部:=var3n and var4n and var5n; 绝对底:=count(百发百中=1,5)=1 and 底部;绝对底部出击:百发百中=1 and 底部=1 ; 20210311
公式如下:在通达信中测试通过。tja:=c>ma(c,5);t**:=c/ref(c,1)>1.05 and c/ref(c,1);tjc:=c>o;tjd:=h/c;xg:tja and t** and tjc and tjd;很的意思啊。居然把我手中的000046选出来了。如果还有什么疑问可以在下面继续追问,如果认为满意的话别忘了点击下方的“选为满意回答”
y1:=barslast(=100000);:=(hhv(c,0),y1+1);vv:=(hhv(v,0),y1+1);:=/dyna**(3)<1.05;zt10:=(c,) and v>vv and ;aa1:=barslast(=110000);cc1:=(hhv(c,0),aa1+1);vv1:=ref(hhv(v,0),aa1+1);1:=cc1/dyna**(3)<1...
ma5:=ma(c,5);ma10:=ma(c,10);ma20:=ma(c,20);ma30:=ma(c,30);ma60:=ma(c,60);选:ma5>ma10 and ma10>ma20 and ma20>ma30 and ma30>ma60 and ma5>ref(ma5,1) and ma10>ref(ma10,1) and ma20>ref(...
m1:=ma(c,5);m2:=ma(c,10);m3:=ma(c,20);m4:=ma(c,30);t1:=count(c>m4,5)=5 and llvbars(m3,5)-hhvbars(m3,5)>3 and hhv(m2,5)/llv(m2,5);t2:=max(max(m1,m2),m3)-min(min(m1,m2),m3);xg:t1=1 and t2=1;