m5:=ma(c,5);m10:=ma(c,10);m24:=ma(c,24);m72:=ma(c,72);b1:=abs(m5-m72)/m72<0.01;b2:=abs(m10-m72)/m72<0.03;b3:=abs(m24-m72)/m72<0.03;x:=b1 and b2 and b3 and c>m72; ex**t(x,3);
amo:=amount;maamo1:=ma(amo,10);maamo2:=ma(amo,20);maamo3:=ma(amo,30); aa:=ma(c,5)>ma(c,10) and ma(c,10)>ma(c,30) and ma(c,30)>ma(c,60) and ma(c,60)>ma(c,120);cross(maamo1,maamo2) and aa a...
公式如下,在通达信中测试通过,你试试。mv5:=ma(v,5);mv10:=ma(v,10);mv20:=ma(v,20);mv30:=ma(v,30);tj1:=mv5>mv10 and mv10>mv20 and mv20>mv30;tj2:=mv5>ref(mv5,1) and mv10>ref(mv10,1) and mv20>ref(mv20,1) a...