小坏蛋_187709549
2024-11-16 19:40:45
最佳回答
1)ref(c,1)>ref(o,1) and ref(h,1)/ref(c,1)>1.02 and ref(h,1)/ref(l,1))>1.02 and ref(h,1)/ref(l,1))<1.05 and o>c and c/l>1.02 and and h/l>1.02 and h/l<1.05; 2) ref(c,1)>ref(o,1) and ref(h,1)/ref(c,1)>1.02 and ref(h,1)/ref(l,1))>1.02 and ref(h,1)/ref(l,1))<1.05 and c<o and c/l>1.02 and and h/l>1.02 and h/l<1.05 and ref(c,1)/ref(o,1)>o/c ; 3) ref(c,1)<ref(o,1) and ref(c,1)/ref(l,1)>1.02 and ref(h,1)/ref(l,1))>1.02 and ref(h,1)/ref(l,1))<1.05 and h/c>1.02 and and h/l>1.02 and h/l<1.05 and c/o<ref(o,1)/ref(c,1); 4) ref(c,2)/ref(c,3)>1.04 and ref(c,2)/ref(o,2)>1.02 and ref(c,1)<ref(o,1) and ref(h,1)/ref(o,1)>1.02 and ref(h,1)/ref(l,1))>1.02 and ref(h,1)/ref(l,1))<1.05 and c<o and c/l>1.02 and h/l>1.02 and h/l<1.05 and ref(h,1)<ref(c,2) and ref(l,1)>ref(o,2) and ref(v,2)>max(v,ref(v,1)); 5) ref(o,1)/ref(c,1)>1.03 and ref(c,1)/ref(c,2)<=0.97 and ref(c,1)/ref(c,2)>=0.93 and o/l>1.02 and c>o and h/l>1.03 and h/l<1.05 and (ref(o,1)-c)/c<=2*((c-ref(c,1))/ref(c,1)); 6) ref(c,1)<ref(o,1) and (ref(h,1)-ref(l,1))>2*(ref(o,1)-ref(c,1)) and c/ref(c,1)>1.04 and c/o>1.03 and ref(v,1)<ref(ma(v,5),1); 7) ref(c,1)<ref(o,1) and ref(c,1)/ref(l,1)>1.02 and ref(h,1)/ref(l,1))>1.02 and ref(h,1)/ref(l,1))<1.05 and c<ref(o,1) and o>ref(c,1) and c>o and c/o<1.02 and (h-l)>2*(c-o) and l>(ref(c,1)+ref(o,1))/2; 以上就是你想要的公式,希望对你帮助。(你选择的一些用词不够量化,比如长下影线或长上影线,没有量化,我仅凭感觉帮你定义了一下,不知是不是你想要的) 20210311