diff:=ema(c,12)-ema(c,26);dea:=ema(diff,9);t:=barslast(dea);dd1:=count(cross(diff,dea),t)>=1 and cross(diff,dea);dd2:=v>ref(ma(v,5),1)*1.5;dd3:=(c/ref(c,1)-1)*100;轴上第一金叉:=cross(diff,dea)and dea&...
公式如下,在通达信中测试通过,你试试。mv5:=ma(v,5);mv10:=ma(v,10);mv20:=ma(v,20);mv30:=ma(v,30);tj1:=mv5>mv10 and mv10>mv20 and mv20>mv30;tj2:=mv5>ref(mv5,1) and mv10>ref(mv10,1) and mv20>ref(mv20,1) a...